WebNov 20, 2024 · I want the names. select sname from (select s.* from sailors s left join reserves r on r.sid = s.sid where r.bid in (101, 102)) t1 But I only want the names of those who have rented both 101 and 102. In this … WebQuestion: Consider the following schema: Sailors (sid: integer, sname: string, rating: integer, age: real) Boats (bid: integer, bname: string, color: string) Reserves (sid: integer, bid: …
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WebFind the names of sailors who have reserved at least one boat. Find the ids of sailors who have reserved a red boat or a green boat. Return the names of the sailors who end with the letter 'y'. Find the names of sailors who have reserved boat 103. Count the number of different sailor names. Calculate the average age of all sailors. WebOct 4, 2024 · 1 Answer. SELECT Sailors.sname FROM Sailors JOIN Reserves ON Sailors.sid = Reserves.sid GROUP BY Sailors.name HAVING count (Reserves.bid) >= 3; EDIT : The logic above aggregates at the sailor name level/granularity (using group by clause) so that the number of reservations can be counted at an aggregate level for … green and cream eyelet curtains
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WebMar 20, 2024 · This unisex Hawaiian name, meaning ‘sea’ has been a lot of buzz lately in the baby name world. It’s currently at #199 spot for boys and #915 for girls. 24. Leif: Leif, … Web62. Count the number of different sailor names. 63. Find the names of sailors who are older than the oldest sailor with a rating of 10. 64. Find the sailors with the highest rating. 65. Find the age of the youngest sailor for each rating level. 66. Find age of the youngest sailor who is eligible to vote for each rating level with at least 2 ... WebFor every sailor in sailors do 1. produce a list of every boat 2. from that list, remove the boats that that particular sailor had reserved If there is nothing in that list (i.e. NOT EXISTS) then the given sailor satisfies the WHERE clause and his or her name can be emitted. green and cream fabric